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3x^2-47x-70=0
a = 3; b = -47; c = -70;
Δ = b2-4ac
Δ = -472-4·3·(-70)
Δ = 3049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-\sqrt{3049}}{2*3}=\frac{47-\sqrt{3049}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+\sqrt{3049}}{2*3}=\frac{47+\sqrt{3049}}{6} $
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